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1.525x^2-0.5x-1=0
a = 1.525; b = -0.5; c = -1;
Δ = b2-4ac
Δ = -0.52-4·1.525·(-1)
Δ = 6.35
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.5)-\sqrt{6.35}}{2*1.525}=\frac{0.5-\sqrt{6.35}}{3.05} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.5)+\sqrt{6.35}}{2*1.525}=\frac{0.5+\sqrt{6.35}}{3.05} $
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